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c = \sqrt{a^2 + b^2} = \sqrt{8^2 + 15^2} = \sqrt{64 + 225} = \sqrt{289} = 17 \ \text{cm}

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Thus the diameter of the circumscribed circle is 17 cm.

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\boxed{17 \ \text{cm}}

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Question:** A square with a side length of 10 cm is inscribed in a circle. Determine the area of the circle.

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Solution:

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When a square is inscribed in a circle the diameter of the circle is equal to the diagonal of the square. We first calculate the diagonal of the square.

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For a square with side length \( s = 10 \) cm the diagonal \( d \) is given by:

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d = s\sqrt{2} = 10\sqrt{2} \ \text{cm}

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