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The diameter of the circle circumscribed around a right triangle is the hypotenuse of the triangle. We apply the Pythagorean theorem to find the hypotenuse.

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Let \( a = 8 \) cm and \( b = 15 \) cm be the legs of the right triangle. The hypotenuse \( c \) is given by:

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c = \sqrt{a^2 + b^2} = \sqrt{8^2 + 15^2} = \sqrt{64 + 225} = \sqrt{289} = 17 \ \text{cm}

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Thus the diameter of the circumscribed circle is 17 cm.

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\boxed{17 \ \text{cm}}

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Question:** A square with a side length of 10 cm is inscribed in a circle. Determine the area of the circle.

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When a square is inscribed in a circle the diameter of the circle is equal to the diagonal of the square. We first calculate the diagonal of the square.

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