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A regular hexagon can be divided into 6 equilateral triangles. The longest diagonal of the hexagon spans across two opposite vertices passing through the center and equals twice the side length.

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Given the side length \( s = 12 \) cm the longest diagonal \( D \) is:

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D = 2 \times 12 = 24 \ \text{cm}

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\boxed{24 \ \text{cm}}

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Question:** A triangle has sides of lengths 13 cm 14 cm and 15 cm. Find the radius of the inscribed circle.

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Solution:

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To find the radius \( r \) of the inscribed circle (inradius) we use the formula:

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